30x^2+98x+45=0

Solution for 30x^2+98x+45=0 equation:

30x^2+98x+45=0

a = 30; b = 98; c = +45;
Δ = b2-4ac
Δ = 982-4·30·45
Δ = 4204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4204}=\sqrt{4*1051}=\sqrt{4}*\sqrt{1051}=2\sqrt{1051}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-2\sqrt{1051}}{2*30}=\frac{-98-2\sqrt{1051}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+2\sqrt{1051}}{2*30}=\frac{-98+2\sqrt{1051}}{60}
$